已知向量OA→=(-2,0),OB→=(2,2),BC→=(2cosθ,2sinθ)(0 ≤θ<2π),则向量OA→与OC→的夹角的取值范围是( ).
(A)[7π/6 ,11π/6].
(B)[7π/12 ,11π/12].
(C)[2π/3 ,5π/3].
(D)[5π/4 ,7π/4].
有以下程序struct S{ int n; int a[20]; };void f(int *a,int n){ int i;for(i=0;i<n-1;i++) a[i]+=i;}main( ){ int i; struct S s={10,{2,3,1,6,8,7,5,4,10,9}};f(s.a,s.n);for(i=0;i<s.n;i++) printf("%d",s.a[i]);}程序运行后的输出结果是A)2,4,3,9,12,12,11,11,18,9,B)3,4,2,7,9,8,6,5,11,10,C)2,3,1,6,8,7,5,4,10,9,D)1,2,3,6,8,7,5,4,10,9,
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在○中填入“<”“>”“=”。4/5-2/5○9/10-7/10 5/8-3/8○3/4-1/43/12+5/12○1/6+3/6 3/7+4/7○4/11+7/11
有以下程序struct S{ int n; int a[20]; }; void f(int *a,int n) {int i; for(i=0;i a[i]+=i; } main() {int i; struct S s={10,{2,3,1,6,8,7,5,4,10,9}}; f(s.a, s.n); for(i=0;i printf(“%d”,s.a[i]); } 程序运行后的输出结果是( )。A.2,4,3,9,12,12,11,11,18,9,B.3,4,2,7,9,8,6,5,11,10,C.2,3,1,6,8,7,5,4,10,9,D.1,2,3,6,8,7,5,4,10,9,
计算:(1) (-3)-(-7); (2)(-10)-3; (3)33-(-27); (4)0 -12; (5)(-11)-0; (6)(-4)-16。
放宽检验一次抽样方案为( )。A.(5,0)B.(3,0)C.(2,2D.(2,0)
计算:(1)(-8)-(-1) (2)45+(-30) (3)-1.5-(-11.5) (4)-1/4-(-1/2) (5)15-[1-(-20-4)] (6)-40-28-(-19)+(-24) (7)22.54+(-4.4)+(-12.54)+4.4 (8) (2/3-1/2)-(1/3-5/6) (9)2.4-(-3/5)+(-3.1)+4/5 (10)(-6/13)+(-7/13)-(-2)(11)3/4-(-11/6)+(-7/3)(12)11+(-22)-3×(-11)(13)(-0.1)÷1/2×(-100)(14)(-3/4)×(-2/3 - 1/3) ×0(15)(-2)3-32(16)23÷[(-2)3-(-4)](17)(3/4-7/8)÷(-7/8)(18)(-60)×(3/4+5/6)
已知aList=[3,4,5,6,7,9,11,13,15,17]则aList[1:2]的结果为:()。A、[4,6,9,13,17]B、[3,4,5,6,7]C、[3,4]D、[3,6,11,17]