现有如下程序段 #include"stdio.h" main() { int a[5][6]={23,3,65,21,6,78,28;5,67,25,435,76,8,22,45,7,8,34,6,78,32,4,5,67,4,21,1}; int i=0,j=5; printf("%d\n",*(&a[0][0]+2*i+j-2));} 则程序的输出结果为
A.21
B.78
C.23
D.28
现有如下程序段#include "stdio.h"main(){ int k[30]={12,324,45,6,768,98,21,34,453,456};int count=0,i=0;while(k[i]){ if(k[i]%2==0‖k[i]%5==0)count++;i++; }printf("%d,%d\n",count,i);}则程序段的输出结果为A.7,8B.8,8C.7,10D.8,10
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现有如下程序段#include "stdio.h"main(){int a[5][6]={23,3,65,21,6,78,28,5,67,25,435,76,8,22,45,7,8,34,6,78,32,4,5,67,4,21,1};int i=0,j=5;printf("%d\n",*(&a[0][0]+2*i+j-2));}则程序的输出结果为A.21B.78C.23D.28
阅读下列程序段,则程序的输出结果为 #include"stdio.h" #defineM(X,Y)(X)*(Y) #defineN(X,Y)(X)/(Y) main() {f int a=5,b=6,c=8,k; k=N(M(a,b),c); printf("%d\n",k);}A.3B.5C.6D.8
为使*p=20,下面正确的程序是()A. include main( ) { int a=10,b=20,*p=&b; printf为使*p=20,下面正确的程序是 ( )A.# include<stdio.h> main( ) { int a=10,b=20,*p=&b; printf("%d\t%d\n",p,*p); } *p)B.# include<stdio.h> main( ) { int a=10,b=20,*p=b; printf("%d\t\%d\n",p,*p) }C.# include<stdio.h> main( ) { int a=10,b=20,*p; p=&a; p + +; printf("%d\t\%d\n",p,*p);} }D.# include<stdio.h> main( ) { int a=10,b=20,*p; *p=20; printf("%d\t\%d\n",p,*p); }
下列程序的运行结果为() include main() {struc tdate {int year,month,day; )today;下列程序的运行结果为( )#include<stdio.h>main(){ struc tdate{int year,month,day;)today;printf("%d\n",sizeof(struct date));}A.8B.6C.10D.12
现有如下程序段,则程序段的输出结果为 【16】 。#include "stdio.h"int fun(){static int k;return k;}main(){int m;m=fun();printf("%d\n",m);}
阅读如下程序段#include "stdio.h"main(){ int x,a,b;scanf("%d",&x);a=b=x;for(;x!=0;){ if(x输入后输出结果是A.a=7569,b=789B.a=5,b=365C.a=7,b=789D.a=7569,b=5